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-16x^2+35x=16
We move all terms to the left:
-16x^2+35x-(16)=0
a = -16; b = 35; c = -16;
Δ = b2-4ac
Δ = 352-4·(-16)·(-16)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{201}}{2*-16}=\frac{-35-\sqrt{201}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{201}}{2*-16}=\frac{-35+\sqrt{201}}{-32} $
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